meaning of assignment from incompatible pointer type

[RESOLVED] assignment from incompatible pointer type
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Assignment from incompatible pointer type

I'm not sure why this is happening, I think I'm doing everything correctly.. Maybe someone can help point me in the right direction.

These are spaced out in the program so I didn't want to copy a bunch of code but if more is needed please let me know.

Shouldn't this work correctly without giving me the incompatible pointer type?

2 What is shm? How is it defined? if it is int textLeft[16] , then it's normal, unsigned short* is NOT the same as signed int[] – Eregrith Dec 19, 2013 at 11:04

3 Answers 3

No, this should not work, because you're assigning an int* value to an unsigned short* variable, which causes undefined behavior per the C strict aliasing rule .

The way to make this work without changing the types is to

But really, I strongly recommend you change the types to be compatible, since otherwise you're tying yourself to a single compiler's extensions to the C standard.

and things are ok.

You're right, I thought I had did that before but it took care of the error. But I remember now I get another error from something else. I get an "Invalid Argument" when before doing int it didn't have that. – user2318083 Dec 19, 2013 at 11:15

In your case x is a unsigned short pointer and textLeft is a signed integer. You are trying to assign signed integer address to unsigned short pointer.

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Assignment from incompatible pointer type (structures, linked list).

Creating a dictionary data structure using a linked list.

Working on the function to add dictionary entries to the linked list.

assigning d->curr to d->curr->next gives me the warning 'assignment from incompatible pointer type'.

What is my mistake here? both curr and next are of the type *dictionary_entry_t

next is a struct dictionary_entry_t * , but d->curr is a dictionary_entry_t * aka struct _dictionary_entry_t * . Note the difference in underscores.

One way to solve this would be to be consistent with your underscores, declaring next as:

However, I prefer a different way: typedef fing before declaring the struct . Then:

ifelse.info

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warning: assignment from incompatible pointer type

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I want to print name and age of person in program Code: #include <stdio.h>#include <stdlib.h> #include <string.h> typedef struct Person { char Name[20]; int Age; int *next; }List; int main() { List *head = NULL; head = (List*)malloc(sizeof(List)); head->Age = 20; strcpy(head->Name,"Abhi\n"); head->next = NULL; while(!head) { printf(" %d ",head->Age); printf(" %s ",head->Name); head = head->next; }; free(head); return(0); } warning: assignment from incompatible pointer type [-Wincompatible-pointer-types] head = head->next; ^ What's wrong in the code ?

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You declared next to be an int* instead of a struct Person*. Also, you should typedef the struct to either Person or Node, not List.

Originally Posted by Bjarne Stroustrup (2000-10-14) I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool. Look up a C++ Reference and learn How To Ask Questions The Smart Way

Originally Posted by laserlight You declared next to be an int* instead of a struct Person*. Also, you should typedef the struct to either Person or Node, not List. Now code compile without warning but It doesn't print name and age Code: #include <stdio.h>#include <stdlib.h> #include <string.h> typedef struct Person { char Name[20]; int Age; struct Person *next; }List; int main() { List *head = NULL; head = (List*)malloc(sizeof(List)); head->Age = 20; strcpy(head->Name,"Abhi\n"); head->next = NULL; while(!head) { printf(" %d ",head->Age); printf(" %s ",head->Name); head = head->next; }; free(head); return(0); }

Your while loop condition should be head, not !head. Actually, you shouldn't use head for this because you need it to keep track of the head of the linked list. Use another node pointer.

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assignment from incompatible pointer type

I am getting a the warning "assignment from incompatible pointer type" when compiling my code, I have spent ages trying everything I can think of, but I am not very experienced at using C so it is probably something really simple that I just can't see.

I have commented the lines that are getting the warning

The "struct queue" inside the typedef refers to an as yet undefined struct.

You need to name your struct, before you can point to it. Fortunately, this is easy to do, like so.

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assignment from incompatible pointer type

I have set up the following structs:

and I get the folowings error: assignment from incompatible pointer type I don't understand why both head and node are the same type: Dictionary.

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change it to this

The reason is that DictionaryList (defined on line 7) and dictionaryList (used on line 11) are different types.

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I want to print name and age of person in program Code: #include #include #include typedef struct Per. What's wrong in the code ?
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typedef struct{ process *data; struct queue *next; } queue; The "struct queue" inside the typedef refers to an as yet undefined struct. You need to name your struct, before you can point to it. Fortunately
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I have set up the following structs:typedef struct lineList { int lineNum; struct lineList* Next; }*Line; typedef struct DictionaryList { char* word; Line lines; struct dictionaryList* Next; }*Dictionary